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- 威望
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设一对中心距为110的齿轮 齿数比为6:5 则大齿轮的参数方程为:x=60*(cos(t)+t*sin(t)) y=60*(sin(t)-t*cos(t)) 根据啮合原理 利用matlab编程 ! f, G" K: ~! e- P
> syms t q$ j% H1 z- h+ E4 X6 z4 h3 u
>> x=60*(cos(t)+t*sin(t))# a8 _$ _7 K! Z1 a! y7 H' g- o9 G- R5 P
7 O* e. O/ y8 e- t6 sx =
/ m$ R% G% m" N1 k0 y+ p; X( m
f7 D% D2 @* x, j% o; r, x! e60*cos(t) + 60*t*sin(t)5 R P- V" ~2 d8 l# ?
9 c! i9 X$ Y, c: r1 o% S
>> y=60*(sin(t)-t*cos(t)): ?" Y- g5 y' T1 k% H% c
% _! p4 i( \' o" K8 h
y =
6 |% f" R2 m; R& p- q$ V( ? & T. O$ i3 [& \: I" h
60*sin(t) - 60*t*cos(t)( D% {5 J z( K# Y
9 `6 O- t7 f2 O, e: j5 `>> x1=-x*cos(11/6*q)-y*sin(11/6*q)+110*cos(q) B+ v4 V% }% O0 D
+ e* M$ ?; z8 R, ~0 Q& r
x1 =9 \, }" y/ k% |) E! g* ]3 |0 j) S4 a, X
/ ?0 v$ |. Q4 x4 b
110*cos(q) - cos((11*q)/6)*(60*cos(t) + 60*t*sin(t)) - sin((11*q)/6)*(60*sin(t) - 60*t*cos(t))* s2 q3 ` |' P0 }) p( j& @
3 p4 |2 F7 V* \5 O>> y1=-x*sin(11/6*q)+y*cos(11/6*q)+110*sin(q)
+ B: P0 J) G7 s
9 k" ?7 z4 S+ ?/ g' ly1 =
1 G( H: a) a! f3 P4 a9 H- n & ]5 H! [/ Y# M6 k
110*sin(q) + cos((11*q)/6)*(60*sin(t) - 60*t*cos(t)) - sin((11*q)/6)*(60*cos(t) + 60*t*sin(t))
l0 I9 m! \% S1 l, T2 `0 ? & l/ l" g8 c8 @8 w
>> diff(x1,t)
8 L+ v6 ?/ h1 F/ w' o+ y
" R8 A) d5 S0 ]; L+ V0 Z/ Zans =
4 G1 y* R$ ^5 c& B* I
. [0 s R) m8 o$ V- 60*t*cos((11*q)/6)*cos(t) - 60*t*sin((11*q)/6)*sin(t)
' c, Q' \% Q. p6 Z2 n & z3 i+ i" l# m) T5 h2 ~, h5 n" v8 E4 g
>> diff(y1,t)' E: |7 J" a' O/ k9 b
) L! O1 i9 b3 y4 `3 t5 J6 b
ans =
$ V0 p! `7 s6 f+ L, p4 t( p
, u7 Q$ ]9 x! |* V( ?( e: ?60*t*cos((11*q)/6)*sin(t) - 60*t*sin((11*q)/6)*cos(t)
; o7 e3 d# l7 X( }; K9 T 7 f2 ^0 x2 d" X" |: R! F
>> diff(x1,q)# p) w. @8 s d% \; }4 |
+ C/ O% v1 M! l5 Vans =& M2 N" Q/ d, z
9 f: J2 ^+ l8 d% ?) v @5 F5 |(11*sin((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - (11*cos((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6 - 110*sin(q)
% g( X9 F4 y* _, Q
$ [) j; D* C5 ~) q* e3 e+ B>> diff(y1,q)
( {2 D8 P/ U( x9 ~- N) M/ @ * x& v1 |3 ~" A
ans =
3 l6 R3 r) s$ T4 T, b, `; M
& f' g- v; W( p% K) x. w I; V110*cos(q) - (11*cos((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - (11*sin((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6- E6 }) f( R4 I/ `/ D
. y% d* }7 u1 R/ v' R( i>> f1=sym('(110*cos(q) - (11*cos((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - (11*sin((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6)*(- 60*t*cos((11*q)/6)*cos(t) - 60*t*sin((11*q)/6)*sin(t))-((11*sin((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - (11*cos((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6 - 110*sin(q))*(60*t*cos((11*q)/6)*sin(t) - 60*t*sin((11*q)/6)*cos(t))')
; y$ Q& z7 g2 Y7 z/ M0 S! k3 t
/ R2 h C' d' Hf1 =
# L, h, Y) l4 w! I V) S0 e- |
& {1 w+ T8 ~0 f* r) Z9 F& E(60*t*cos((11*q)/6)*cos(t) + 60*t*sin((11*q)/6)*sin(t))*((11*cos((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - 110*cos(q) + (11*sin((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6) + (60*t*cos((11*q)/6)*sin(t) - 60*t*sin((11*q)/6)*cos(t))*(110*sin(q) + (11*cos((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6 - (11*sin((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6)' x" S7 N* e1 i7 h) q+ l* G5 L
- N. S; S0 E+ `( a5 e9 f2 Y8 e
>> simplify(f1)
! I, G. y f" O$ B+ u
( A7 O' \, s+ f) X% L- K! Zans =7 e( ~' S7 X' i* P' V. F2 s
9 w! B; ~( `; j8 {! E' X
-6600*t*(cos((5*q)/6 - t) - 1)
$ n: a* l+ m: h( ?7 j; T0 g
# K; J# a C: Q, b' T -6600*t*(cos((5*q)/6 - t) - 1)=0 解得q=6/5*t 代入 x1=-x*cos(11/6*q)-y*sin(11/6*q)+110*cos(q) 0 U/ f! U- }* ]$ {( {6 s( F
y1=-x*sin(11/6*q)+y*cos(11/6*q)+110*sin(q) 5 I Z0 Y0 B) r
化简后得X1=50*(cos(1.2*t)+1.2*t*sin(1.2*t)) y=50*(sin(1.2*t)-1.2*t*cos(1.2*t))+ B9 k! q2 O4 m2 x
从方程上可以看出小齿轮的方程仍为渐开线 |
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